POJ 2549 Sumsets

该不能偷懒的时候就不能偷懒

POJ 2549 Sumsets

题目描述

求集合中 $A[i] + A[j] + A[k] = A[l]$ 的 $l$ ,要求 $A[i] \neq A[j] \neq A[k] \neq A[l]$。

题解

将上述等式转换为 $A[i] + A[j] = A[l] - A[k]$ ,对于 $l, k$ 两个维度进行枚举。因为没有问这些元素在序列的位置,所以直接排序,从大到小直接枚举即可。(不用判断 $A[l]$ 与 $A[k]$ 的关系,因为集合中的元素会出现负数)

AC Code

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
144
145
146
147
148
149
150
151
152
153
154
155
156
157
158
159
160
161
162
163
164
165
166
167
168
169
170
171
172
173
174
175
176
177
#define NOSTDCPP
//#define Cpp11
//#define Linux_System
#ifndef NOSTDCPP
#include <bits/stdc++.h>
#else
#include <algorithm>
#include <bitset>
#include <cassert>
#include <climits>
#include <complex>
#include <cstring>
#include <cstdio>
#include <deque>
#include <exception>
#include <functional>
#include <iomanip>
#include <iostream>
#include <istream>
#include <iterator>
#include <list>
#include <map>
#include <ostream>
#include <queue>
#include <set>
#include <sstream>
#include <stack>
#include <string>
#include <typeinfo>
#include <utility>
#include <valarray>
#include <vector>
#endif
# ifdef Linux_System
# define getchar getchar_unlocked
# define putchar putchar_unlocked
# endif
# define RESET(_) memset(_, 0, sizeof(_))
# define RESET_(_, val) memset(_, val, sizeof(_))
# define fi first
# define se second
# define pb push_back
# define midf(x, y) ((x + y) >> 1)
# define DXA(_) ((_ << 1))
# define DXB(_) ((_ << 1) | 1)
# define next __Chtholly__
# define x1 __Mercury__
# define y1 __bbtl04__
# define index __ikooo__
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef vector <int> vi;
typedef set <int> si;
typedef pair <int, int> pii;
typedef long double ld;
const int MOD = 1e9 + 7;
const int maxn = 1009;
const int maxm = 300009;
const int inf = 1e9;
const double pi = acos(-1.0);
const double eps = 1e-6;
ll myrand(ll mod){return ((ll)rand() << 32 ^ (ll)rand() << 16 ^ rand()) % mod;}
template <class T>
inline bool scan_d(T & ret)
{
char c;
int sgn;
if(c = getchar(), c == EOF)return false;
while(c != '-' && (c < '0' || c > '9'))c = getchar();
sgn = (c == '-') ? -1 : 1;
ret = (c == '-') ? 0 : (c - '0');
while(c = getchar(), c >= '0' && c <= '9')
ret = ret * 10 + (c - '0');
ret *= sgn;
return true;
}
#ifdef Cpp11
template <class T, class ... Args>
inline bool scan_d(T & ret, Args & ... args)
{
scan_d(ret);
scan_d(args...);
}
#define cin.tie(0); cin.tie(nullptr);
#define cout.tie(0); cout.tie(nullptr);
#endif
inline bool scan_ch(char &ch)
{
if(ch = getchar(), ch == EOF)return false;
while(ch == ' ' || ch == '\n')ch = getchar();
return true;
}
template <class T>
inline void out_number(T x)
{
if(x < 0)
{
putchar('-');
out_number(- x);
return ;
}
if(x > 9)out_number(x / 10);
putchar(x % 10 + '0');
}
int n, ans, l, r;
int A[maxn];
int main()
{
while(scanf("%d", &n) && n)
{
ans = -inf;
for(int i = 1; i <= n; ++ i) scanf("%d", A + i);
if(n <= 3) {puts("no solution"); continue;}
sort(A + 1, A + 1 + n);
for(int i = n; i >= 1; -- i)
{
for(int j = n; j >= 1; -- j)
{
if(i == j) continue;
l = 1, r = j - 1;
while(l < r)
{
if(A[l] + A[r] == A[i] - A[j]) {ans = A[i]; break;}
if(A[l] + A[r] < A[i] - A[j]) ++ l;
else -- r;
}
if(ans != -inf) break;
}
if(ans != -inf) break;
}
/*
if(A[1] < 0)
{
for(int i = 1; i <= n; ++ i)
for(int j = i + 1; j <= n; ++ j)
{
if(i == j) continue;
l = j + 1, r = n;
while(l < r)
{
if(A[l] + A[r] == A[i] - A[j]) {ans = A[i]; break;}
if(A[l] + A[r] < A[i] - A[j]) ++ l;
else -- r;
}
if(ans != -inf) break;
}
}
*/
ans == -inf ? puts("no solution") : printf("%d\n", ans);
}
return 0;
}
/*
5
2 3 5 7 12
5
2 16 64 256 1024
6
-6 -5 -4 -3 -2 -1
0
*/
文章目录
  1. 1. POJ 2549 Sumsets
    1. 1.1. 题目描述
    2. 1.2. 题解
    3. 1.3. AC Code
{{ live2d() }}